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  • 07-04-2018
  • Mathematics
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what is one to one and how do i solve this in steps?

what is one to one and how do i solve this in steps class=

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Аноним Аноним
  • 07-04-2018
[tex]f(x) = \dfrac{7}{x+2} [/tex]

[tex]y = \dfrac{7}{x+2} [/tex]

[tex]y(x + 2) = 7[/tex]

[tex]xy + 2y = 7[/tex]

[tex]xy = 7 - 2y[/tex]

[tex]x = \dfrac{7 - 2y}{y} [/tex]

[tex]f^{-1}(x) = \dfrac{7 - 2x}{x} [/tex]

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