carleycates2 carleycates2
  • 07-03-2018
  • Mathematics
contestada

Factor completely 2x3 + x2 - 18x - 9

A. (x2-9)(2x+1)
B. (x-3)(x+3)(2x-1)
C. (x-3)(x+3)(2x+1)
D. (2x-3)(2x+3)(x-1)

Respuesta :

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zrh2sfo zrh2sfo
  • 07-03-2018
Factor the following:
2 x^3 + x^2 - 18 x - 9

Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)

Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)

x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)

Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):

Answer:  (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
Answer Link
4804167154
4804167154 4804167154
  • 15-06-2020

Answer:

(x - 3) (x + 3) (2 x + 1) thus the Answer is C.

Step-by-step explanation:

Answer Link

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