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08-02-2018
Mathematics

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T = 2π √l/g Re-arrange to make l the subject.

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sqdancefan sqdancefan

08-02-2018

[tex] T = 2 \pi \sqrt{ \frac{l}{g}} [/tex]
[tex] \frac{T}{2 \pi} = \sqrt{ \frac{l}{g}} [/tex]
[tex] ( \frac{T}{2 \pi} )^{2} = \frac{l}{g} [/tex]
[tex] l = g \times ( \frac{T}{2 \pi} )^{2} [/tex]

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