Respuesta :

stevekimaz
So you want to solve for x?

It would be nice if this would easily factor:
(-4x + 5)(2x +1)  = 0    This will not work!

So you need to use the quadratic formula:
a = -8, b = 4, c = 5

[tex] x = \frac{-b+/- \sqrt{b^{2}-4ac} }{2a}[/tex]

x = (-4 +/- [tex] \sqrt{16-4(-8)(5)} [/tex])/2(-8)
   = (-4 +/- [tex] \sqrt{16 + 160} [/tex])/-16
   = (-4 +[tex] \sqrt{176} [/tex])/-16
   = 1/4 - [tex] \sqrt{11} [/tex]/4

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