11-01-2018
Mathematics

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what are the steps to solve
[tex] \sqrt{20 {k}^{3} } [/tex]

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jdoe0001 jdoe0001

11-01-2018

[tex]\bf \sqrt{20k^3}\qquad \begin{cases} 20=2\cdot 2\cdot 5\\ \qquad 2^2\cdot 5\\ k^3=k^{2+1}\\ \qquad k^2\cdot k^1 \end{cases}\implies \sqrt{2^2\cdot 5\cdot k^2\cdot k}\implies 2k\sqrt{5k}[/tex]

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