Respuesta :

Edufirst
Assuming the right expression is

 [cos(theta) + cos(theta) ]^2 + [cos(theta) + cos(theta)]^2, the solution is:

[2cos(theta)]^2 + [2cos(theta)]^2 = 4 [cos(theta)]^2 + 4 [cos(theta)]^2 =startin

= 8 [cos(theta)]^2.

If the starting expression is different, please type it and the list of choices again, making sure that the operators can be understood unambiguosly.

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