mac98
mac98
06-02-2017
Mathematics
contestada
Evaluate the following 12!/9!3!
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LammettHash
LammettHash
06-02-2017
[tex]\dfrac{12!}{9!3!}=\dfrac{12\times11\times10\times9!}{9!3!}=\dfrac{12\times11\times10}{3!}=\dfrac{6\times2\times11\times10}{3\times2\times1}=2\times11\times10=220[/tex]
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