What is f(x) = 8x² + 4x written in vertex form?
F(x) = 8x + - 1.

f(x) = 8√(x + 1)² - 1/6

f(x) = 8√x+¹²-2

f(x) = 8(x + 1)² - 4

Question

07-07-2022
Mathematics

contestada

What is f(x) = 8x² + 4x written in vertex form?
F(x) = 8x + - 1.

f(x) = 8√(x + 1)² - 1/6

f(x) = 8√x+¹²-2

f(x) = 8(x + 1)² - 4

Respuesta :

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Medunno13 Medunno13 · Answer 1 · 2022-07-09T18:26:38+02:00

Medunno13 Medunno13

09-07-2022

[tex]8x^{2}+4x\\\\=8\left(x^{2}+\frac{1}{2}x \right)\\\\=8\left(x+\frac{1}{4} \right)^{2}-8\left(\frac{1}{16} \right)\\\\\boxed{f(x)=8\left(x+\frac{1}{4} \right)^{2}-\frac{1}{2}}[/tex]

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What is f(x) = 8x² + 4x written in vertex form? F(x) = 8x + - 1. f(x) = 8√(x + 1)² - 1/6 f(x) = 8√x+¹²-2 f(x) = 8(x + 1)² - 4

Respuesta :

Otras preguntas

What is f(x) = 8x² + 4x written in vertex form?
F(x) = 8x + - 1.

f(x) = 8√(x + 1)² - 1/6

f(x) = 8√x+¹²-2

f(x) = 8(x + 1)² - 4