roquidatodecheene roquidatodecheene

10-05-2022
Mathematics

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Find the center and radius for each equation of a circle (X+2)^2+y^2=13

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davidmaharjan62 davidmaharjan62

10-05-2022

Step-by-step explanation:

[tex](x + 2) {}^{2} + {y}^{2} = 13 \\ comparing \: the \: equation \: with \: \\ (x - h) {}^{2} + (y - k) {}^{2} = r {}^{2} \\ center(h \: k) = ( - 2 \:\:\: 0) \\ r = \sqrt{13} [/tex]

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