YagaYeetin YagaYeetin

10-05-2022
Mathematics

contestada

Given [tex]sinx=-\frac{15}{17}[/tex] and cos x > 0, what is the exact solution of cos 2x?
[tex]A. \frac{161}{289} B.\frac{225}{289} C.-\frac{161}{289} D.-\frac{225}{289}[/tex]

Respuesta :

LammettHash LammettHash

12-05-2022

Recall that

cos(2x) = 1 - 2 sin²(x)

so given that sin(x) = -15/17, we have

cos(2x) = 1 - 2 (-15/17)² = -161/289

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