syahbanazacki
syahbanazacki syahbanazacki
  • 10-01-2022
  • Mathematics
contestada

Can u solve this? Please don't spam
[tex] \: [/tex]
[tex] \int \frac{8x - 4}{4} \: dx[/tex]
​

Respuesta :

jimrgrant1 jimrgrant1
  • 10-01-2022

Answer:

x² - x + c

Step-by-step explanation:

Using the power rule for integration

∫ a[tex]x^{n}[/tex] dx = [tex]\frac{a}{n+1}[/tex] [tex]x^{n+1}[/tex]

∫ [tex]\frac{8x-4}{4}[/tex] dx ( divide terms on numerator by 4 )

= ∫ (2x - 1) dx

= [tex]\frac{2}{2}[/tex] [tex]x^{1+1}[/tex] - x + c

= x² - x + c ( c is the constant of integration )

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