tepAveierTheholmo tepAveierTheholmo
  • 07-01-2017
  • Physics
contestada

A wave travels a distance of 60cm in 3s. The distance blw successive crests of thd wave is 4cm. What is the frequency?

Respuesta :

dexteright02
dexteright02 dexteright02
  • 08-01-2017
Data:
ΔS = 60cm
Δt = 3s
Vm = ?

Vm = ΔS/Δt 
[tex]Vm = \frac{60}{3} [/tex]
[tex]Vm = 20cm/s[/tex]

We have:

Vm = v
ΔS = λ
Δt = T

[tex]v = \frac{\lambda}{T} [/tex]
[tex]20 = \frac{\lambda}{4} [/tex]
[tex]\lambda = 20*4[/tex]
[tex]\lambda = 80cm[/tex]

Soon:

[tex]v = \lambda*f[/tex]
[tex]20 = 80*f[/tex]
[tex]80f = 20[/tex]
[tex]f = \frac{20}{80} simplify( \frac{\div20}{\div20} )= \frac{1}{4} [/tex]
[tex]\boxed{f = 0,25Hz}[/tex]


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