Respuesta :

MrAayush

Answer:

4x-3y+12=0 is required eqn

Step-by-step explanation:

Let, 3,8 be x1,y1

9,16 be x2,y2

Now,

Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)

y-8 = 16-8/9-3 * (x-3)

y-8 = 4/3*(x-3)

3y-24 = 4x-12

4x-3y+12=0 is required eqn