Answer:
0.302M
Explanation:
Molarity, which is the molar concentration of a solution can be calculated as follows:
Molarity = number of moles (n) ÷ volume (V)
According to this question, 19.5 grams of Be(OH)2 is dissolved in enough water to make a 1.5 L solution.
Using mole = mass/molar mass to calculate the number of moles in 19.5g of Be(OH)2
Molar mass of Be(OH)2 = 9 + (16 + 1)2
= 9 + (17)2
= 9 + 34
= 43g/mol
mole = 19.5/43
mole = 0.453moles
Molarity = n/V
Molarity = 0.453/1.5
Molarity = 0.302M
