Respuesta :

Answer:

60m³b²

Step-by-step explanation:

We need to find the least common multiple of 15 m³ and 12 b².

Prime factorization of 15 m³ = 3×5×m³

Prime factorization of 12 b² = 3×2×2×b²

Common = 3×5×m³×2×2×b²

= 60m³b²

So, the least common multiple of 15 m³ and 12 b² is equal to 60m³b².