Respuesta :

sinararios2006

Answer

B

203.403

Cancel terms that are in both the numerator and denominator

( 2 1 0 0 ) + ( 3 1 ) + ( 4 1/1 0 ) + ( 3 1/1 0 0 0 )

( 2 1 0 0 ) + ( 3 1 ) + ( 2 1/5 ) + ( 3 1/1 0 0 0 )

Solution

( 2 1 0 0 ) + ( 3 1 ) + ( 2 1/5 ) + ( 3 1/1 0 0 0 )

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