microcker87 microcker87
  • 10-12-2020
  • Chemistry
contestada

What isotope is the product of the alpha (*2He) nuclear decay of Radon-222 (222U)?
222 Rn
86
a +
2

What isotope is the product of the alpha 2He nuclear decay of Radon222 222U 222 Rn 86 a 2 class=

Respuesta :

Eduard22sly
Eduard22sly Eduard22sly
  • 15-12-2020

Answer:

ⁿₐX => ²¹⁸₈₄Po

Explanation:

Let ⁿₐX be the isotope.

Thus, the equation can be written as follow:

²²²₈₆Rn —> ⁴₂α + ⁿₐX

Next, we shall determine the value of 'n' and 'a'. This can be obtained as follow:

222 = 4 + n

Collect like terms

222 – 4 = n

218 = n

Thus,

n = 218

86 = 2 + a

Collect like terms

86 – 2 = a

84 = a

Thus,

a = 84

ⁿₐX => ²¹⁸₈₄Po

²²²₈₆Rn —> ⁴₂α + ⁿₐX

²²²₈₆Rn —> ⁴₂α + ²¹⁸₈₄Po

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