Answer:
2.07 × 10³ cal
Explanation:
Step 1: Given and required data
- Initial temperature: 37.0 °C
- Final temperature: 92.0 °C
- Specific heat capacity of aluminum (c): 0.215 cal/g.°C
Step 2: Calculate the change in the temperature experienced by the aluminum piece
ΔT = 92.0 °C - 37.0 °C = 55.0 °C
Step 3: Calculate the heat required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.215 cal/g.°C × 175 g × 55.0 °C
Q = 2.07 × 10³ cal
