Answer:
f(0)= 7.071
Step-by-step explanation:
We are given: [tex]f(x)=2(x)^2+5\sqrt{(x+2)}[/tex]
We need to find f(0)
For finding f(0) put x=0
[tex]f(x)=2(x)^2+5\sqrt{(x+2)}\\Put \ x=0\\f(0)=2(0)^2+5\sqrt{0+2} \\f(0)=2(0)^2+5\sqrt{2}\\f(0)=0+5\sqrt{2}\\f(0)=5(1.4142)\\f(0)=7.071\\[/tex]
So, we get f(0)= 7.071
