edward6549 edward6549
  • 07-12-2020
  • Chemistry
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Calculate the amount of energy needed to boil 2352.00 g of liquid oxygen

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pstnonsonjoku
pstnonsonjoku pstnonsonjoku
  • 08-12-2020

Answer:

500976 J

Explanation:

Mass of Oxygen= 2352.00 g/1000 = 2.352 Kg

Heat of vaporization of oxygen = 213 kJ kg − 1

The heat of vaporization of a substance refers to the amount of heat required to  boil  1  Kg of a given substance at its boiling point.

Thus energy required to boil 2.352 Kg of oxygen = 2.352 Kg * 213 kJ kg − 1  = 500.976 KJ

To convert this to J = 500.976 KJ * 10^3 = 500976 J

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