jdarreol
contestada

A cannonball is launched at ground level at an angle of 30° above the horizontal with
an initial velocity of 26 m/s. How far does the cannonball travel horizontally before it
reaches the ground?
Vi =26m/s g = 9.8m/s^2 vf=0
30°

Respuesta :

Answer:

use the kinematics equations and solve for time, after that use dleta dx=Vi*delta time

Use the kemetic equation