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06-08-2020
Mathematics

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solve 3(x +15) ≤5(x+2) + 15

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Yisrael777 Yisrael777

06-08-2020

Answer:

x≥5

Step-by-step explanation:

3(x+15)≤5(x+2)+15

3x+45≤5x+10+15

3x+35≤5x+25

3x-5x≤25-35

-2x≤-10

x≥5

{x:xEx:6,7,8,9,10....}

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