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Consider The reaction Cu2O(s) + C (s) ------> 2 Cu (s) + CO (g)



When 11,5 g of C are allowed to react with 114,5 g of Cu2O, 87,4 g of Cu are obtained.Find

the limiting reactant,

Respuesta :

Cu2O (s)   +   C (s)     ---->     2Cu (s)   +   CO (g)

Find the moles of each:

11.5g of Carbon

n(C) = mass / Molar mass

n(C) = 11.5 / 12.01 = 0.95753587

114.5g of Copper I Oxide

n(Cu2O) = mass / Molar mass

n(Cu2O) = 114.5 / 143.1 = 0.800139762

87.4g of Copper

n(Cu) = mass / Molar mass

n(Cu) = 87.4 / 63.55 = 1.375295043

Carbon has less moles compared to Copper I Oxide, therefore Carbon is the limiting reagent

dhanyaj

Answer:

Carbon is the limiting reagent

Explanation:

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