Answer:
[tex]12.25 r^2 [/tex] kg where r (cm) is the radius of the puck
Explanation:
Assuming the radius of the puck is r (cm), we can first calculate the volume v of the puck as the product of its base area a and the height h
[tex]v = ah = \pi r^2 h[/tex] cubic centimetres
Then the mass m of the puck would be product of the volume and the puck density ρ
[tex]m = v\rho = \pi r^2 h \rho = 1.5*2.6 \pi r^2 = 12.25 r^2 [/tex]kg
