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The orbital period of an object is 2 x 10^7 and its total radius is 4 x 10^4 m.
m/s. (Round to the nearest whole number, do not add any punctuation)
The tangential speed of the satellite is ______ m/s

Respuesta :

Answer:

12566

Explanation:

Use formula: vt=2pir/t

ce6751ps905

Answer:

12,566 not 12560 because edgenuity doesnt want you to round by the tenths only by the ones

Explanation:

Because 2* pi * 4x10^10 = 251327412400 (Dont round the pi to 3.14)

and divide it by 2x10^7

you get 12,566.37 which its 12,566 (and dont add punctuation, stated on the quiz)

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