Answer:
D
Explanation:
Weight of atmosphere would apply pressure on Earth's Surface
P = F/A
P=Atm pressure , F= force , A= area
Let mass M
M x g / A = P
g= 9.81 m/s^2
A is the surface area of a sphere = 4 x π x r^2
r= radius of earth
Putting values
[tex]M\times9.8/4\times3.14\times(6.37\times10^6)^2 =1.013\times10^5[/tex]
∴ M = 5.26 x 10^18 Kg
We know that total mass of Earth is 6×10^24 Kg.
Therefore we can say that The atmosphere accounts for:0.00009% of the total mass of the planet. Option D is correct.
