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08-02-2020
Mathematics

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find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

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Aaqib10 Aaqib10

08-02-2020

Answer:

13, 15, 17

Step-by-step explanation:

x(x + 4) = 10(x + 2) + 71

x2 + 4x = 10x + 20 + 71

x2 - 6x - 91 = 0

(x + 7)(x - 13) = 0

x + 7 = 0

x = -7

-7, -5, -3

x - 13 = 0

x = 13

13, 15, 17

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