Answer:
Therefore 9th term of the geometric sequence is [tex]\frac{2}{2187}[/tex]
Step-by-step explanation:
Given first term(a) = 6
and common ratio = [tex]\frac{1}{3}[/tex]
[tex]T_n= ar^{n-1}[/tex]
[tex]\therefore T_9=ar^{9-1}[/tex]
[tex]\Leftrightarrow T_9=a r^8[/tex]
[tex]\Leftrightarrow T_9=6\times ( \frac{1}{3}) ^8[/tex]
[tex]\Leftrightarrow T_9=\frac{2}{2187}[/tex]
Therefore 9th term of the geometric sequence is [tex]\frac{2}{2187}[/tex]
