jkplant4792 jkplant4792
  • 16-01-2020
  • Physics
contestada

If the monthly electricity consumption of a household is 6,619 kWh, what is this consumption expressed in kJ

Respuesta :

sebasacevedop
sebasacevedop sebasacevedop
  • 16-01-2020

Answer:

[tex]2.38*10^{4}kJ[/tex]

Explanation:

One watt equals to 1 joule per second. So, one kilowatt equals 1 kilojoule per second. Thus, one kilowatt-hour is equivalent to:

[tex]1kWh=1\frac{kJ}{s}*3600s=3600kJ[/tex]

Finally, we can calculate the monthly electricity consumption in kJ:

[tex]6,619kWh*\frac{3600kJ}{1kWh}=2.38*10^{4}kJ[/tex]

Answer Link

Otras preguntas

What do you know about the civil rights movement of the 1950s-60s
Which sentence is written correctly? The city, supposedly filled with gold, was a fable and the tired explorers would never find it. The city, supposedly filled
Use the periodic table to find the numbers of protons, neutrons, and electrons for atoms of the following elements.
i need help????????????????????
The value of a stock increased by $4.90, and then decreased by $7.35. What was the net change in value of the stock?
How is a Domestic challenge different from a foreign challenge?
In George’s classroom, there are 6 girls for every 2 boys. What is the ratio of boys to the total number of students?
How much is 10% of 65 gallons? Write your answer as a decimal number.
If (72)p = 76, what is the value of p? (5 points)
7k - 14 = 42 I need help solving this equation , can you help ?