joygil80 joygil80
  • 09-01-2020
  • Mathematics
contestada

What are the zeros of the quadratic function f(x)=2x^2+8x-3

Respuesta :

PollyP52 PollyP52
  • 09-01-2020

Answer:

-2 +/-  [(sqrt 88)/ 4]

or

0.35, -4.35 to the nearest hundredth.

Step-by-step explanation:

2x^2 + 8x - 3 = 0

Using the quadratic formula:

x = [ -8 +/- sqrt (8^2 - 4*2*-3) ] / 4

=  -2 +/-  (sqrt 88)/ 4

Answer Link
morgannelynnwyllie morgannelynnwyllie
  • 17-03-2021

C on edg 2021

this is too detailed, i’m not writing it out

Answer Link

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