Answer:
[tex]v=\sqrt{2gH}\dfrac{mB}{mM+mB}[/tex]
Explanation:
Given that
Mass of first block = mB
Mass of second block = mM
Height = H
The speed of the mass m just before the collision
[tex]V=\sqrt{2gH}[/tex]
There is no any external force on the masses that is why the linear momentum will be conserve.
Initial linear momentum = Final linear momentum
Pi = mB V
lets take the final speed of the system becomes v
Pf= (mM+mB) v
m V = (mM+mB) v
[tex]v=\sqrt{2gH}\dfrac{mB}{mM+mB}[/tex]
