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When tightening a bolt, you push perpendicularly on a wrench with a force of 165 N at a distance of 0.140 m from the center of the bolt? (a) How much torque are you exerting in newtons x meters (relative to the center of the bolt) (b) Convert this torque to footpounds

Respuesta :

Answer:

Part a)

[tex]\tau = 23.1 Nm[/tex]

Part b)

[tex]\tau = 17.05 Foot pound force[/tex]

Explanation:

As we know that torque is defined as the product of force and its perpendicular distance from reference point

so here we have

[tex]\tau = \vec r \times \vec F[/tex]

now we have

[tex]\tau = (0.140)(165)[/tex]

[tex]\tau = 23.1 Nm[/tex]

Part b)

Now we know the conversion as

1 meter = 3.28 foot

1 N = 0.225 Lb force

now we have

[tex]\tau = 23.1 Nm[/tex]

[tex]\tau = 23.1 (0.225 Lb)(3.28 foot)[/tex]

[tex]\tau = 17.05 Foot pound force[/tex]

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