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09-07-2019
Physics

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A force of 32.5N stretches a spring of 0.500cm. What force will stretch a similar spring 1.60 cm?

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MathPhys MathPhys

09-07-2019

Answer:

104 N

Explanation:

Calculate the spring stiffness:

F = kx

32.5 N = k (0.500 cm)

k = 65 N/cm

Find the force for the new length:

F = kx

F = (65 N/cm) (1.60 cm)

F = 104 N

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