brooklyn1737
brooklyn1737
07-11-2018
Mathematics
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What is the answer please help
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fafhaa
fafhaa
07-11-2018
[tex] \sqrt{ - 48} = \sqrt{ - 1} \sqrt{48} = i \sqrt{(16)(3)} \\ = i \sqrt{16} \sqrt{3} = i \sqrt{ {4}^{2} } \sqrt{3} \\ = i4 \sqrt{3} = 4i \sqrt{3} [/tex]
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