kimberly73s kimberly73s
  • 09-08-2018
  • Mathematics
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prove a/b is less than b/a when 0 < a <b

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bawbdmo
bawbdmo bawbdmo
  • 09-08-2018

[tex] \frac{a}{b} < \frac{b}{a} \implies \\
a^2 < b^2 \implies
a<b \lor -a>-b [/tex]

We are given that 0<a<b, which means that 0>-a>-b if you multiply it by -1, which means what's given by our inequality is true and we are done.

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