petriajack8008 petriajack8008
  • 08-07-2018
  • Mathematics
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(−14x^3y^3+4x^5 y6)÷(2x^4y^5)

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claudettoterohil
claudettoterohil claudettoterohil
  • 08-07-2018
( - 14x^3)(y^3) + 4x^5y^6)/(2x^4y^5)

= 4x^5y^6  - 14x^3y^3/2x^4y^5


= 4x^2y^3  - 14/2xy^2


= 2x^2y^3  - 7/xy^2


Answer:   2x^2y^3 - 7/xy^2




Hope that helps!!!!
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