Respuesta :

gustanika
Use combination to solve it
13C10 = [tex] \dfrac{13!}{10! \times (13-10)!} [/tex]
13C10 = [tex] \dfrac{13 \times 12 \times 11 \times 10!}{10! \times 3!} [/tex]
13C10 = [tex] \dfrac{13 \times 12 \times 11}{3!} [/tex]
13C10 = [tex] \dfrac{13 \times 12 \times 11}{3 \times 2 \times 1} [/tex]
13C10 = [tex] \dfrac{1716}{6} [/tex]
13C10 = 286
There are 286 ways